That's easy. The answer is A: 2024. The other answers would require either the zero or the four to be plural.
65
[deleted] - 17hr
B: 0044 is both plural which is as consistent as A: 2024
9
spencerwi @feddit.org - 17hr
I think he's saying that the clue would need to be "two zeroes, two fours"
43
Diplomjodler - 17hr
That's what always bothered me about exams. They're always about what the examiner wants to hear and not about what is right.
67
Dadifer @lemmy.world - 16hr
So just put what the examiner is thinking, obviously
26
Whelks_chance @lemmy.world - 16hr
School trains you for real life. Repeat back what your boss told you, in a confident enough way to make it sound like you understand what's happening.
21
Dadifer @lemmy.world - 15hr
Exactly
4
dejected_warp_core @lemmy.world - 12hr
For me, it was always where the teacher had to add their own flair and/or questions on top of the textbook ones. They were always the most ambiguous to answer, and cost everyone points. Of course, in American public school, we're not taught to challenge our elders and call bullshit when we see it. So everyone takes the -5% on the chin, except that one kid that accidentally got that one right.
I was going to say, if this were in a Layton game there would be some trick answer like his face.
15
Skullgrid @lemmy.world - 18hr
optimism : every answer is right
Pessimism : every answer is wrong
33
IrateAnteater @sh.itjust.works - 18hr
Physicists: all three answers are both right and wrong up until the point when they are evaluated.
23
Entertainmeonly - 16hr
Schrodingers multiple choice?
2
Farid - 16hr
I would go with C, because:
A) Not filled
B) Doesn't have 4 sides/corners (or sum of angles is less than 360 deg.)
C) Isn't red AND the only shape with all right(ish) angles
So C is most unlike the others.
27
BakerBagel @midwest.social - 16hr
C does have 4 sides and 4 corners and all of its corners add up to 360°, same as A since the interior angles of all quadrilaterals add up to 360°
24
funkless_eck @sh.itjust.works - 15hr
I think OP is saying it doesn't have smooth sides or corners and is not a quad at all, but actually an irregular polygon due to the jittered sides and overlapping corners.
4
Redjard - 13hr
C is regular, A and B are irregular
4
Farid - 15hr
Yes, that's exactly what I said. B doesn't have those things you mentioned, meaning A and C do.
3
tetris11 @feddit.uk - 16hr
I would also go with C, but for different reasons:
A) is the only one not filled in
B) is the only three sided
C) can partner easily with A and B
so C because he's the most chill
6
Farid - 14hr
But all of them can equally be partnered with any other, because if you don't count the right angle difference they all have the same amount of differences and are equally "chill".
6
tetris11 @feddit.uk - 14hr
Oh! I genuinely did not notice color. Fair point.
I still think Rectangle-chan gives spicy BigBoi vibes that I jell with more, but I respect the correction
3
Farid - 14hr
Green color and less pointy corners definitely makes it look more friendly.
3
Windex007 @lemmy.world - 8hr
This comment is cursed
2
MumboJumbo @lemmy.world - 18hr
Reminds of the game Set. It's a card game, but there are many online versions. I loved this game while growing up.
15
BootLoop @sh.itjust.works - 17hr
Good game
5
mumblerfish @lemmy.world - 18hr
I played this as a card game so much in high school. Real nice with an online version. Thank you.
4
stray @pawb.social - 9hr
I've seen this before as a minigame and cannot play it. I would like a version of the game where you're presented with three cards and asked to identify whether or not they're a set, with no time limit, so that my brain might have a chance to develop whatever skill I'm lacking. I'm currently having to brute-force combinations, which is far too slow a method with the time limit. (Which was also the case for said minigames.)
But mostly I'm curious what the nature of my impairment is, because I think it's psychologically interesting.
e: I've been doing some experimentation and reading. I'm fine at identifying whether any three cards are or aren't a set, so that method of practice wouldn't help. I think I may have identified autism as the problem, specifically issues with global processing and parallel feature integration. Can any other autists share their experience with the game?
You can make a private room here to play by yourself as slow as you want! :D
1
MountingSuspicion @reddthat.com - 13hr
Numberphile did a video about this game and to my recollection the person presenting it actually had a distinct game of set they and their math friends would play. It was pretty interesting!
1
Ceruleum @lemmy.wtf - 15hr
Pick the gender fluid one.
5
Saapas - 18hr
This new captcha is less annoying than the one before
5
Fandangalo @lemmy.world - 17hr
I gave up posting last night after failing 3 times in a row.
4
sp3ctr4l @lemmy.dbzer0.com - 16hr
... only one choice is green.
How is this difficult, other than if you are r/g colorblind?
The correct choice is C.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick B, A is also red, and C is also filled solid with color. So B is not unlike either B or C.
But if you pick C, while C does have elements in common with A and B...
(it shares 'irregular 4-gon' with A, and 'solid color fill' with B)
... it is also unlike each of them singly, as well as both of them together, in that it is green.
C is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
4
KaChilde @sh.itjust.works - 15hr
... only one choice is a triangle.
How is this difficult, other than if you are shape blind?
The correct choice is B.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick B, while B does have elements in common with A and C...
(it shares 'red' with A, and 'solid color fill' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
B is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
23
KaChilde @sh.itjust.works - 15hr
What a fool you are!
... only one choice is an outline.
How is this difficult, other than if you are line blind?
The correct choice is A.
If you pick B, A is also red, and C is also a filled solid. So B is not unlike either A or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick A, while A does have elements in common with B and C...
(it shares 'red' with B, and '4-gon' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
A is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
22
sp3ctr4l @lemmy.dbzer0.com - 15hr
Welp.
I tap out, you're right lol.
Don't attempt set theory before breakfast, otherwise you end up making a fool of yourself as I have.
=[
Hangry is not a useful state to approach logic from.
12
canofcam @lemmy.world - 16hr
2 shapes are the same colour
2 shapes are filled
2 shapes have four sides
the point of this is that there are multiple distinct properties not found in any member of the remainder set
19
sp3ctr4l @lemmy.dbzer0.com - 15hr
No.
You are wrong.
"Select the image that is unlike the other two."
The only possible choice that results in a set of 2, and a set of 1, which are seperated cleanly by a distinct property, is picking C.
The goal is to define a difference between potential sets such that a distinct property exists between the two sets that you create.
To define two sets where unlikeness exists between them when they are compared.
Your job is not to merely compare three elements.
It is to compare three possible pairs of sets that can be made out of three elements.
Which elements have which particular combinations of attributes is thus very important, not irrelevant, as your simplified description of the situation portrays.
1
fonix232 - 15hr
And that's literally what they did.
There's a set of shapes that are filled, and a distinct set of one that is outline only.
There's a set of shapes that have 4 sides, and a distinct set of one that is 3 sides only.
There's a set of shapes that are red, and a distinct set of one shape that is green.
14
sp3ctr4l @lemmy.dbzer0.com - 15hr
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick B, A is also red, and C is also filled solid with color. So B is not unlike either B or C.
But if you pick C, while C does have elements in common with A and B...
(it shares 'irregular 4-gon' with A, and 'solid color fill' with B)
... it is also unlike each of them singly, as well as both of them together, in that it is green.
Only when you pick C do you result in a pair of sets that are cleanly dvided by the same property difference.
Is that more clear?
If you pick C, the distinction between C and A is the same distinction between C and B.
Thus, if you pick C, C is unlike A and B in the same way.
This is what I would call a clean or clear distinction, or ... kind of unlikeness.
This is not the case, does not occur, if you pick A or B.
You end up with a picked set of one element that differs from the remainder set in ways that are inconsistent among the elements of the remainder set.
IE, a muddled or inconsistent distinction.
1
fonix232 - 15hr
No, you're still not correct just because you chose to reduce the similarities of C with A and B.
Again, I can make the same ignorant reduction of importance you did, but from a different aspect, and get a different answer.
The only reason you're picking C is psychological, as in, C is the most visually distinct due to the difference in colour (which is something human eyes are keyed towards). The rest of your explanation is a pseudointellectual attempt of forcing logic into your subjective choice, basically, you're Petersoning it real hard just to be right.
Just to make it clear, let's apply your same property difference.
If you pick A, the distinction between (A, B) and (A, C) is the same - they are filled, not outline.
If you pick B, the distinction between (B, A) and (B, C) is the same again - they have four sides, not 3.
So, again, the same property difference pair can be applied to literally any of the choices.
9
sp3ctr4l @lemmy.dbzer0.com - 15hr
Yep, you're right.
KaChilde ran through a more thorough version of my own logic and I realized I am being a stubborn ass, sorry about that lol!
9
fonix232 - 15hr
Well, I'm glad this moment led to some personal growth!
Remember, making mistakes is okay as long as you 1, can admit being wrong and 2, learn from being wrong.
And to be fair this "puzzle" is specifically designed to be confusing and have people jump to the "obvious conclusion" based on their perspective. To you it was the colour green vs red, to others it was the shape triangle vs quadrangle, and to a third group it would be the outline vs filled state. It's actually not unlike some IQ test questions where the goal isn't to see if you can find the "correct" answer (as there isn't one!), but to see how you think.
RmDebArc_5 in greentext @sh.itjust.works
Anon plays Professor Layton
https://piefedimages.s3.eu-central-003.backblazeb2.com/posts/L7/cT/L7cTk3h4Ab5lw6C.webphttps://sh.itjust.works/pictrs/image/c557fd42-55f1-4691-9c4f-4bbb785ab380.jpeg
That's easy. The answer is A: 2024. The other answers would require either the zero or the four to be plural.
B: 0044 is both plural which is as consistent as A: 2024
I think he's saying that the clue would need to be "two zeroes, two fours"
That's what always bothered me about exams. They're always about what the examiner wants to hear and not about what is right.
So just put what the examiner is thinking, obviously
School trains you for real life. Repeat back what your boss told you, in a confident enough way to make it sound like you understand what's happening.
Exactly
For me, it was always where the teacher had to add their own flair and/or questions on top of the textbook ones. They were always the most ambiguous to answer, and cost everyone points. Of course, in American public school, we're not taught to challenge our elders and call bullshit when we see it. So everyone takes the -5% on the chin, except that one kid that accidentally got that one right.
https://lemmy.world/pictrs/image/a29840a9-f4de-4396-83bc-facdcce2a17d.png
I was going to say, if this were in a Layton game there would be some trick answer like his face.
optimism : every answer is right
Pessimism : every answer is wrong
Physicists: all three answers are both right and wrong up until the point when they are evaluated.
Schrodingers multiple choice?
I would go with C, because:
A) Not filled
B) Doesn't have 4 sides/corners (or sum of angles is less than 360 deg.)
C) Isn't red AND the only shape with all right(ish) angles
So C is most unlike the others.
C does have 4 sides and 4 corners and all of its corners add up to 360°, same as A since the interior angles of all quadrilaterals add up to 360°
I think OP is saying it doesn't have smooth sides or corners and is not a quad at all, but actually an irregular polygon due to the jittered sides and overlapping corners.
C is regular, A and B are irregular
Yes, that's exactly what I said. B doesn't have those things you mentioned, meaning A and C do.
I would also go with C, but for different reasons:
A) is the only one not filled in
B) is the only three sided
C) can partner easily with A and B
so C because he's the most chill
But all of them can equally be partnered with any other, because if you don't count the right angle difference they all have the same amount of differences and are equally "chill".
Oh! I genuinely did not notice color. Fair point.
I still think Rectangle-chan gives spicy BigBoi vibes that I jell with more, but I respect the correction
Green color and less pointy corners definitely makes it look more friendly.
This comment is cursed
Reminds of the game Set. It's a card game, but there are many online versions. I loved this game while growing up.
Good game
I played this as a card game so much in high school. Real nice with an online version. Thank you.
I've seen this before as a minigame and cannot play it. I would like a version of the game where you're presented with three cards and asked to identify whether or not they're a set, with no time limit, so that my brain might have a chance to develop whatever skill I'm lacking. I'm currently having to brute-force combinations, which is far too slow a method with the time limit. (Which was also the case for said minigames.)
But mostly I'm curious what the nature of my impairment is, because I think it's psychologically interesting.
e: I've been doing some experimentation and reading. I'm fine at identifying whether any three cards are or aren't a set, so that method of practice wouldn't help. I think I may have identified autism as the problem, specifically issues with global processing and parallel feature integration. Can any other autists share their experience with the game?
e: !!!
https://setwithfriends.com/game/fun-hospitable-grip
You can make a private room here to play by yourself as slow as you want! :D
Numberphile did a video about this game and to my recollection the person presenting it actually had a distinct game of set they and their math friends would play. It was pretty interesting!
Pick the gender fluid one.
This new captcha is less annoying than the one before
I gave up posting last night after failing 3 times in a row.
... only one choice is green.
How is this difficult, other than if you are r/g colorblind?
The correct choice is C.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick B, A is also red, and C is also filled solid with color. So B is not unlike either B or C.
But if you pick C, while C does have elements in common with A and B...
(it shares 'irregular 4-gon' with A, and 'solid color fill' with B)
... it is also unlike each of them singly, as well as both of them together, in that it is green.
C is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
... only one choice is a triangle.
How is this difficult, other than if you are shape blind?
The correct choice is B.
If you pick A, B is also red, and C is also an irregular 4-gon. So A is not unlike either B or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick B, while B does have elements in common with A and C...
(it shares 'red' with A, and 'solid color fill' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
B is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
What a fool you are!
... only one choice is an outline.
How is this difficult, other than if you are line blind?
The correct choice is A.
If you pick B, A is also red, and C is also a filled solid. So B is not unlike either A or C.
If you pick C, A is also an irregular 4-gon, and B is also filled solid with color. So C is not unlike either A or B.
But if you pick A, while A does have elements in common with B and C...
(it shares 'red' with B, and '4-gon' with C)
... it is also unlike each of them singly, as well as both of them together, in that it is a triangle.
A is the only choice where 'is unlike the other two'... is true, in any sense.
It has a distinct property, not found in any member of the remainder set, nor shared by the remainder set as a group.
Welp.
I tap out, you're right lol.
Don't attempt set theory before breakfast, otherwise you end up making a fool of yourself as I have.
=[
Hangry is not a useful state to approach logic from.
2 shapes are the same colour
2 shapes are filled
2 shapes have four sides
the point of this is that there are multiple distinct properties not found in any member of the remainder set
No.
You are wrong.
"Select the image that is unlike the other two."
The only possible choice that results in a set of 2, and a set of 1, which are seperated cleanly by a distinct property, is picking C.
The goal is to define a difference between potential sets such that a distinct property exists between the two sets that you create.
To define two sets where unlikeness exists between them when they are compared.
Your job is not to merely compare three elements.
It is to compare three possible pairs of sets that can be made out of three elements.
Which elements have which particular combinations of attributes is thus very important, not irrelevant, as your simplified description of the situation portrays.
And that's literally what they did.
There's a set of shapes that are filled, and a distinct set of one that is outline only.
There's a set of shapes that have 4 sides, and a distinct set of one that is 3 sides only.
There's a set of shapes that are red, and a distinct set of one shape that is green.
Only when you pick C do you result in a pair of sets that are cleanly dvided by the same property difference.
Is that more clear?
If you pick C, the distinction between C and A is the same distinction between C and B.
Thus, if you pick C, C is unlike A and B in the same way.
This is what I would call a clean or clear distinction, or ... kind of unlikeness.
This is not the case, does not occur, if you pick A or B.
You end up with a picked set of one element that differs from the remainder set in ways that are inconsistent among the elements of the remainder set.
IE, a muddled or inconsistent distinction.
No, you're still not correct just because you chose to reduce the similarities of C with A and B.
Again, I can make the same ignorant reduction of importance you did, but from a different aspect, and get a different answer.
The only reason you're picking C is psychological, as in, C is the most visually distinct due to the difference in colour (which is something human eyes are keyed towards). The rest of your explanation is a pseudointellectual attempt of forcing logic into your subjective choice, basically, you're Petersoning it real hard just to be right.
Just to make it clear, let's apply your same property difference.
If you pick A, the distinction between (A, B) and (A, C) is the same - they are filled, not outline.
If you pick B, the distinction between (B, A) and (B, C) is the same again - they have four sides, not 3.
So, again, the same property difference pair can be applied to literally any of the choices.
Yep, you're right.
KaChilde ran through a more thorough version of my own logic and I realized I am being a stubborn ass, sorry about that lol!
Well, I'm glad this moment led to some personal growth!
Remember, making mistakes is okay as long as you 1, can admit being wrong and 2, learn from being wrong.
And to be fair this "puzzle" is specifically designed to be confusing and have people jump to the "obvious conclusion" based on their perspective. To you it was the colour green vs red, to others it was the shape triangle vs quadrangle, and to a third group it would be the outline vs filled state. It's actually not unlike some IQ test questions where the goal isn't to see if you can find the "correct" answer (as there isn't one!), but to see how you think.
I think you are overthinking this mate.
I concur, and realized my logic is flawed.
... sorry.
I could see 1 or 3 being the answer. But not 2.
2 has 3 sides instead of 4
Now imagine being colorblind...